破解存储过程,存储过程解密

MSSQL中遇到存储过程加密如何破解？

exec 所创建的用于解密的存储过程（你找的代码） 要解密的存储过程

就ok楽

如何破解SQL2008的存储过程的存储过程

1个简单的存储过程新建例子:

CREATE procedure sp_getOrders

2 @orderID int = null

3 as

4 if (@orderID is null )

5 begin

6 print 'null'

7 end

8 else

9 begin

10 print 'correct'

11 end

12 select * from Orders where OrderID = @orderID

13 go

修改只要把CREATE procedure替换成alter procedure就可以了。

求破解sql200加密存储过程的具体方法

破解SQL SERVER 加密存储过程,函数,触发器,视图

create PROCEDURE sp_decrypt(@objectName varchar(50))

AS

begin

set nocount on

--破解字节不受限制，适用于SQLSERVER2000存储过程，函数，视图，触发器

begin tran

declare @objectname1 varchar(100),@orgvarbin varbinary(8000)

declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)

DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)

declare @i int,@status int,@type varchar(10),@parentid int

declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int

select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)

create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)

insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)

select @number=max(number) from #temp

set @k=0

while @k=@number

begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)

begin

if @type=\'P\'

set @sql1=(case when @number1 then \'ALTER PROCEDURE \'+ @objectName +\';\'+rtrim(@k)+\' WITH ENCRYPTION AS \'

else \'ALTER PROCEDURE \'+ @objectName+\' WITH ENCRYPTION AS \'

end)

if @type=\'TR\'

set @sql1=\'ALTER TRIGGER \'+@objectname+\' ON \'+OBJECT_NAME(@parentid)+\' WITH ENCRYPTION FOR INSERT AS PRINT 1 \'

if @type=\'FN\' or @type=\'TF\' or @type=\'IF\'

set @sql1=(case @type when \'TF\' then

\'ALTER FUNCTION \'+ @objectName+\'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end \'

when \'FN\' then

\'ALTER FUNCTION \'+ @objectName+\'(@a char(1)) returns char(1) with encryption as begin return @a end\'

when \'IF\' then

\'ALTER FUNCTION \'+ @objectName+\'(@a char(1)) returns table with encryption as return select @a as a\'

end)

if @type=\'V\'

set @sql1=\'ALTER VIEW \'+@objectname+\' WITH ENCRYPTION AS SELECT 1 as f\'

set @q=len(@sql1)

set @sql1=@sql1+REPLICATE(\'-\',4000-@q)

select @sql2=REPLICATE(\'-\',8000)

set @sql3=\'exec(@sql1\'

select @colid=max(colid) from #temp where number=@k

set @n=1

while @n=CEILING(1.0*(@colid-1)/2) and len(@sQL3)=3996

begin

set @sql3=@sql3+\'+@\'

set @n=@n+1

end

set @sql3=@sql3+\')\'

exec sp_executesql @sql3,N\'@Sql1 nvarchar(4000),@ varchar(8000)\',@sql1=@sql1,@=@sql2

end

set @k=@k+1

end

set @k=0

while @k=@number

begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)

begin

select @colid=max(colid) from #temp where number=@k

set @n=1

while @n=@colid

begin

select @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp WHERE colid=@n and number=@k

SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectName) and colid=@n and number=@k)

if @n=1

begin

if @type=\'P\'

SET @OrigSpText2=(case when @number1 then \'CREATE PROCEDURE \'+ @objectName +\';\'+rtrim(@k)+\' WITH ENCRYPTION AS \'

else \'CREATE PROCEDURE \'+ @objectName +\' WITH ENCRYPTION AS \'

end)

if @type=\'FN\' or @type=\'TF\' or @type=\'IF\'--刚才有错改一下

SET @OrigSpText2=(case @type when \'TF\' then

\'CREATE FUNCTION \'+ @objectName+\'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end \'

when \'FN\' then

\'CREATE FUNCTION \'+ @objectName+\'(@a char(1)) returns char(1) with encryption as begin return @a end\'

when \'IF\' then

\'CREATE FUNCTION \'+ @objectName+\'(@a char(1)) returns table with encryption as return select @a as a\'

end)

if @type=\'TR\'

set @OrigSpText2=\'CREATE TRIGGER \'+@objectname+\' ON \'+OBJECT_NAME(@parentid)+\' WITH ENCRYPTION FOR INSERT AS PRINT 1 \'

if @type=\'V\'

set @OrigSpText2=\'CREATE VIEW \'+@objectname+\' WITH ENCRYPTION AS SELECT 1 as f\'

set @q=4000-len(@OrigSpText2)

set @OrigSpText2=@OrigSpText2+REPLICATE(\'-\',@q)

end

else

begin

SET @OrigSpText2=REPLICATE(\'-\', 4000)

end

SET @i=1

SET @resultsp = replicate(N\'A\', (datalength(@OrigSpText1) / 2))

WHILE @i=datalength(@OrigSpText1)/2

BEGIN

SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^

(UNICODE(substring(@OrigSpText2, @i, 1)) ^

UNICODE(substring(@OrigSpText3, @i, 1)))))

SET @i=@i+1

END

set @orgvarbin=cast(@OrigSpText1 as varbinary(8000))

set @resultsp=(case when @encrypted=1

then @resultsp

else convert(nvarchar(4000),case when @status2=2 then uncompress(@orgvarbin) else @orgvarbin end)

end)

print @resultsp

set @n=@n+1

end

end

set @k=@k+1

end

drop table #temp

rollback tran

end

SQLSERVER存储过程加密后，是不是任意版本都可以很容易解密

是的到目前为止，SQL Server所有版本的存储过程的加密的机理都是一样的，都可以被非常容易的破解，前提是，有读取存储过程的代码的权。

要防止用户得到SQL Server存储过程的真实代码，最简单的做法就是只给执行权，不给查看权。

至于安装在别人服务器上的SQL Server数据库中的存储过程，想不让别人看，那基本上是没门儿的。

怎么破解sqlserver加密的存储过程

在另外一台电脑上装数据库，然后将加密所在存储的数据库恢复上去即可。